BODMAS Exercise 24


	BODMAS Exercise 24

Answer to BODMAS Exercise 24

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Solve the following equation using BODMAS or BEMA	Brackets
((65+30)/(10+50)-100/2)-2--5	Of
Solution:	Division
((30+30)/(10+50)-100/2)*-2--5	Multiplication
(60/(10+50)-100/2)*-2--5	Addition
(60/60-100/2)*-2--5	Subtraction
(1-100/2)*-2--5
(1-50)*-2--5
-49*-2--5
98--5 OR 98+5
=103

Note 1: Multiplying a negative number by another negative number always returns a positive result, i.e. -49*-2 = 98 not -98

Note 2: Subtracting a negative number, equals the same as adding the positive amount of that number, i.e. 98--5 is the same as 98+5, both equal 103

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